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In order for transcription to be initiated


A) DNA polymerase must have access to the DNA double helix and must also be capable of binding to the gene's promoter.
B) RNA polymerase must have access to the DNA double helix and must also be capable of binding to the gene's promoter.
C) DNA polymerase must have access to the RNA and must also be capable of binding to the gene's promoter.
D) RNA ligase must have access to the DNA double helix and must also be capable of binding to the gene's promoter.
E) RNA polymerase must have access to the DNA double helix and also must be capable of binding to the gene's operator.

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Transcriptional control-proteins increase the rate of transcription by binding to


A) mRNA sequences within the DNA.
B) tRNA sequences within the DNA.
C) operator sequences within the DNA.
D) promoter sequences within the DNA.
E) enhancer sequences within the DNA.

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Control of the lac operon and lactose utilization in bacteria is (check all that apply)


A) not induced in the presence of both glucose and lactose.
B) only induced when there is glucose but not lactose.
C) is a negative control,mediated by a repressor.
D) controlled by the expression of three downstream genes.
E) preferentially utilizing lactose as a carbon source.

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A site of negative genetic regulation where binding by repressor blocks transcription is the


A) operon.
B) repressor.
C) promoter.
D) operator.
E) CAP.

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Control of gene expression (check all that apply)


A) allows bacteria to adapt to changing environments.
B) is critical for development in multicellular organisms.
C) allows bacteria to replicate without control.
D) allows multicellular organisms to maintain homeostasis.
E) it stops multicellular organisms functioning as a whole.

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A bacterial gene regulatory system is likely to have (check all that apply)


A) a coding sequence.
B) an operator.
C) one or more introns.
D) a motor.
E) a ribosome recognition site.

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If you were able to look very closely at a portion of DNA and find methylated histones,you would


A) be mistaken since only DNA can be methylated,not histones.
B) be looking at a region of active chromatin.
C) be looking at a region of inactive chromatin.
D) be looking at a chromatin remodeling complex.

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The hallmark of multicellular organisms is their ability to


A) grow and divide rapidly.
B) adjust quickly to outside environment.
C) maintain homeostasis.
D) quickly synthesize amount and type of enzymes according to available nutrients.
E) respond by gene action to oxygen availability.

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Small RNAs can regulate gene expression.One type,called micro RNA (miRNA) ,acts by binding directly to


A) mRNA to prevent translation.
B) tRNA to prevent transcription.
C) mRNA to prevent transcription.
D) tRNA to prevent translation.

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The gene encoding apolipoprotein B exists in two isoforms,APOB100 and APOB48.These two forms are produced as a result of


A) tissue-specific expression.
B) a gene mutation that results in a stop codon.
C) RNA editing.
D) alternative splicing.

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You work for a pharmaceutical company that designs small RNAs,used to control expression of disease genes.The primary focus area of your research should be


A) transcriptional repression.
B) transcriptional activation.
C) translational repression.
D) translational activation.

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In eukaryotes,specific transcription factors have two distinct domains:


A) a DNA-binding domain and a RNA-binding domain.
B) a DNA-binding domain and an activation domain.
C) a DNA-binding domain and a repressor domain.
D) a DNA-binding domain and an enhancer domain.
E) a DNA-binding domain and an operator domain.

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The main form of glucose repression in the lac operon is


A) induction.
B) repression.
C) inducer exclusion.
D) the CAP/cAMP system.

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The ubiquitin-proteasome pathway (check all that apply)


A) is used to regulate expression of a number of cell surface receptors.
B) requires only one molecule of ATP to target a protein.
C) targets proteins in a stepwise fashion via ubiquitin ligase adding ubiquitin residues to the protein.
D) is used to digest macromolecules.
E) does not destroy the ubiquitin moiety,but rather cleaves it off for reuse.

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The lactose analog isopropyl-beta-D-thio-galactoside (IPTG) is often used to regulate gene expression systems in bacteria.IPTG does not act as a substrate for beta-galactosidase,but can bind to,and inactivate,the repressor.In this case,IPTG serves as a(n)


A) inducer.
B) repressor.
C) DNA-binding protein.
D) operon.

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You are studying the function of a recently identified gene in C.elegans.You perform genetic screens for several months in an attempt to isolate loss-of-function gene mutations,but your efforts are unsuccessful.Your advisor suggests you try another approach to eliminate gene function.The best technique to accomplish this goal would be


A) to design a repressor to bind to the operon of this gene.
B) use a histone deacetylase to induce a transcriptionally inactive state.
C) use a C.elegans strain with a homozygous TFIID mutation to prevent the translation initiation complex from forming.
D) use RNA interference to prevent mRNA translation.

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Production of the iron-storing protein ferritin is regulated by aconitase,which binds to a 30-nucleotide sequence at the beginning of the ferritin mRNA and interferes with ribosome binding.Aconitase must be a


A) transcription repressor protein.
B) translation repressor protein.
C) RNA interference protein.
D) translation initiation protein.

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The DNA-binding proteins of almost all regulatory proteins use one of a small set of shapes that enable them to fit into the DNA major groove.These shapes are called


A) structural motifs.
B) DNA prints.
C) fingerprints.
D) repressors.
E) transcriptional domains.

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The eukaryotic transcription initiation complex is (check all that apply)


A) transcription of virtually all genes transcribed by RNA pol II requiring the same suite of general factors.
B) responsible for highly regulated transcription levels.
C) only associated with RNA polymerase I.
D) interactive with activators through DNA looping.
E) a basal factor associated with RNA pol II after positioning RNA pol II at the start site.

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If a strain of bacteria had a mutation that blocked expression of the lac repressor,what would you expect as a result?


A) The mutant strain would outcompete wildype strains,since it could always utilize lactose.
B) The mutant strain would grow at the same rate as wildtype if lactose was not present.
C) The mutant strain would waste energy producing enzymes in the absence of lactose.
D) The mutant strain would act the same,because it would still require lac activator protein to turn on.

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