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Which one of the following would be expected to have the lowest standard molar entropy, S°, at 25 °C?


A) C10H22(s)
B) C10H22(l)
C) C14H30(s)
D) C14 Which one of the following would be expected to have the lowest standard molar entropy, S°, at 25 °C? A)  C<sub>10</sub>H<sub>22</sub>(s)  B)  C<sub>10</sub>H<sub>22</sub>(l)  C)  C<sub>14</sub>H<sub>30</sub>(s)  D)  C<sub>14</sub> <sub> </sub>   OH(l) OH(l)

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Which one of the following has the highest standard molar entropy, S°, at 25 °C?


A) NH3(g)
B) Ne(g)
C) SO2(g)
D) CH3CH2OH(g)
E) He (g)

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Which of the following is true for ΔrG?


A) If ΔrG > 0, the reaction is spontaneous in the forward direction.
B) If Q = 1, then DrG > ΔrG.
C) If ΔrG ≠ 0, the reaction is spontaneous in both the reverse and forward directions.
D) If ΔrG < 0, the reaction is spontaneous in the reverse direction.
E) Under equilibrium conditions, ΔrG = 0.

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Calculate ΔrG for the evaporation of methanol at 25°C under nonstandard conditions when Calculate Δ<sub>r</sub>G for the evaporation of methanol at 25°C under nonstandard conditions when   = 150.0 mbar CH<sub>3</sub>OH(l)  → CH<sub>3</sub>OH(g)  A)  -0.40 kJ mol<sup>-1</sup> B)  +9.0 kJ mol<sup>-1</sup> C)  -0.47 kJ mol<sup>-1</sup> D)  +4.3 kJ mol<sup>-1</sup> E)  +16 kJ mol<sup>-1</sup> = 150.0 mbar CH3OH(l) → CH3OH(g)


A) -0.40 kJ mol-1
B) +9.0 kJ mol-1
C) -0.47 kJ mol-1
D) +4.3 kJ mol-1
E) +16 kJ mol-1

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Place the following in order of increasing molar entropy at 298 K. Ne Xe He Ar Kr


A) He < Kr < Ne < Ar < Xe
B) Xe < Kr < Ar < Ne < He
C) Ar < He < Ar < Ne < Kr
D) Ar < Ne < Xe < Kr < He
E) He < Ne < Ar < Kr < Xe

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Which one of the following has the highest standard molar entropy, S°, at 25 °C?


A) H2(g)
B) F2(g)
C) O2(g)
D) N2(g)
E) Cl2(g)

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For the following example, what is true about ΔrH and ΔrS? H2O(l) → H2O(s)


A) a negative ΔrH and a negative ΔrS
B) a positive ΔrH and a negative ΔrS
C) a negative ΔrH and a positive ΔrS
D) a positive ΔrH and a positive ΔrS
E) ΔrH = 0 and a positive ΔrS

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Calculate the equilibrium constant for the following reaction at 525 K: 2H2S(g) → 2H2(g) + S2(g) ΔrH° = 169.8 kJ mol-1; ΔrS°= 78.0 J K-1 mol-1


A) 3.84 × 10-11
B) 1.51 × 10-13
C) 4.08 × 10-17
D) 7.52 × 10-19
E) 6.18 × 10-15

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Calculate ΔrS° for the following reaction. The S° for each species is shown below the reaction. N2H4(l) + H2(g) → 2NH3(g) S° (J K-1 mol-1) 121.2 130.7 192.8


A) +133.7 J K-1 mol-1
B) -59.1 J K-1 mol-1
C) +118.2 J K-1 mol-1
D) -202.3 J K-1 mol-1
E) +178.9 J K-1 mol-1

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Use the following thermodynamic values to calculate Δr NEWLINE Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ  . Δr Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ  = -95 kJ Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ  , Δr Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ  = -157 J Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ  , T = 855 K


A) -48 kJ Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ
B) -68 kJ Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ
C) +39 kJ Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ
D) -157 kJ Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ
E) +142 kJ Use the following thermodynamic values to calculate Δ<sub>r</sub> <sub>NE</sub><sub>WLINE</sub>   . Δ<sub>r</sub> <sub> </sub>   = -95 kJ   , Δ<sub>r</sub> <sub> </sub>   = -157 J   , T = 855 K A)  -48 kJ   B)  -68 kJ   C)  +39 kJ   D)  -157 kJ   E)  +142 kJ

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Calculate the equilibrium constant for the following reaction at 525 K: 2CO(g) + O2(g) → 2CO2(g) ΔrH° = -566 kJ mol-1; ΔrS°= -173 J K-1 mol-1


A) 3.61 × 1058
B) 1.90 × 1047
C) 2.47 × 1014
D) 7.56 × 1084
E) 8.49 × 106

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Above what temperature does the following reaction become nonspontaneous? 2H2S(g) + 3O2(g) → 2SO2(g) + 2H2O(g) ΔrH = -1036 kJ; ΔrS = -153.2 J K-1 mol-1


A) 6.762 × 103 K
B) 158.7 K
C) 298 K
D) 67.62 K
E) 1.587 × 103 K

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Determine the equilibrium constant for the following reaction at 655 K: HCN(g) + 2H2(g) → CH3NH2(g) ΔrH° = -158 kJ mol-1; ΔrS°= -219.9 J K-1 mol-1


A) 3.99 × 1012
B) 13.0
C) 2.51 × 10-13
D) 3.26 × 10-12
E) 3.07 × 1011

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Determine the Q of a reaction at 298 K if ΔrG = -3.5 kJ mol-1 and ΔrG° = +19.3 kJ mol-1.


A) 0.10
B) 0.0010
C) 0.00010
D) 0.34
E) 0.89

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Determine ΔrG° at 298 K using the following information: 2KClO3(s) → 2KCl(s) + 3O2(g) ΔrH°= -77.6 kJ mol-1; ΔrS°= +494.6 J K-1 mol-1


A) -225.0 kJ mol-1
B) +68.4 .0 kJ mol-1
C) -89.3 kJ mol-1
D) +131.5 kJ mol-1
E) +175.2 kJ mol-1

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Match the following. -Q = K


A) standard state
B) equilibrium
C) ΔrG > Δr
D) ΔrG > 0
E) DrG < 0
F) K = 0
G) ΔrG < Δr

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What is "free" energy? Give a fictitious example.

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Consider a reaction that is exothermic (...

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For a given reaction, ΔrH = -19.5 kJ mol-1 and ΔrS = -55.8 J K-1 mol-1. The reaction will have For a given reaction, Δ<sub>r</sub>H = -19.5 kJ mol<sup>-1</sup> and Δ<sub>r</sub>S = -55.8 J K<sup>-</sup><sup>1</sup> mol<sup>-1</sup>. The reaction will have   at   Assume that Δ<sub>r</sub>H and Δ<sub>r</sub>S do not vary with temperature. A)  2.86 B)  0.349 C)  298 D)  2.86 × 10<sup>3</sup> E)  349 at For a given reaction, Δ<sub>r</sub>H = -19.5 kJ mol<sup>-1</sup> and Δ<sub>r</sub>S = -55.8 J K<sup>-</sup><sup>1</sup> mol<sup>-1</sup>. The reaction will have   at   Assume that Δ<sub>r</sub>H and Δ<sub>r</sub>S do not vary with temperature. A)  2.86 B)  0.349 C)  298 D)  2.86 × 10<sup>3</sup> E)  349 Assume that ΔrH and ΔrS do not vary with temperature.


A) 2.86
B) 0.349
C) 298
D) 2.86 × 103
E) 349

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Under which of the following conditions would one mole of He have the highest entropy, S?


A) 17 °C and 15 L
B) 127 °C and 15 L
C) 17 °C and 25 L
D) 127 °C and 25 L

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Calculate ΔrS° for the following reaction. The S° for each species is shown below the reaction. C2H2(g) + H2(g) → C2H4(g) S°(J J K-1 mol-1) 200.9 130.7 219.3


A) +112.3 J K-1 mol-1
B) +550.9 J K-1 mol-1
C) -112.3 J K-1 mol-1
D) +337.1 J K-1 mol-1
E) -550.9 J K-1 mol-1

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