Filters
Question type

Study Flashcards

In which one of the following pairs will the first system have a higher entropy than the second? Assume P and T are the same for each pair, unless stated otherwise.


A) 1 mole He(g) ; 1 mole Kr(g)
B) 1 mole O2(g) ; 2 mole O(g)
C) 1 mole CH4(g) ; 1 mole C2H6(g)
D) 1 mole Xe(g) at 1 atmosphere; 1 mole Xe(g) at 0.5 atmosphere
E) 20 one-dollar bills distributed randomly among 20 people; 20 one-dollar bills distributed randomly among 10 people

Correct Answer

verifed

verified

Elemental boron can be formed by reaction of boron trichloride with hydrogen.  Elemental boron can be formed by reaction of boron trichloride with hydrogen.     If  \Delta S \degree   = 80.3 J/K for the reaction above, what is S  \degree  for BCl<sub>3</sub>(g) ? A)  -18.2 J/K*mol B)  18.2 J/K*mol C)  290.1 J/K*mol D)  355.4 J/K*mol E)  450.6 J/K*mol  Elemental boron can be formed by reaction of boron trichloride with hydrogen.     If  \Delta S \degree   = 80.3 J/K for the reaction above, what is S  \degree  for BCl<sub>3</sub>(g) ? A)  -18.2 J/K*mol B)  18.2 J/K*mol C)  290.1 J/K*mol D)  355.4 J/K*mol E)  450.6 J/K*mol If Δ\Delta S °\degree = 80.3 J/K for the reaction above, what is S °\degree for BCl3(g) ?


A) -18.2 J/K*mol
B) 18.2 J/K*mol
C) 290.1 J/K*mol
D) 355.4 J/K*mol
E) 450.6 J/K*mol

Correct Answer

verifed

verified

A chemical reaction has Δ\Delta H °\degree = 42.8 kJ and Δ\Delta S °\degree = 92.5 J/K, at 25 °\degree C. Calculate the temperature at which Δ\Delta G °\degree = 0. State any approximation involved in your calculation.

Correct Answer

verifed

verified

T = 463 K. The calculation is ...

View Answer

Which of the following values is based on the Third Law of Thermodynamics?


A) ( Δ\Delta H °\degree f = 0 for Al(s) at 298 K)
B) ( Δ\Delta G °\degree f = 0 for H2(g) at 298 K)
C) (S °\degree = 51.446 J/(mol·K) for Na(s) at 298 K)
D) (q sys < 0 for H2O(l) \rightarrow H2O(s) at 0 °\degree C)
E) None of these choices is correct.

Correct Answer

verifed

verified

Consider the figure below which shows Δ\Delta G °\degree for a chemical process plotted against absolute temperature.  Consider the figure below which shows  \Delta G \degree  for a chemical process plotted against absolute temperature.   From this plot, it is reasonable to conclude that: A) (  \Delta H \degree  > 0,  \Delta S \degree  > 0)  B)  ( \Delta H \degree  > 0,  \Delta S \degree  < 0)  C)  ( \Delta H \degree < 0,  \Delta S \degree > 0)  D)  ( \Delta H \degree  < 0,  \Delta S \degree  < 0)  E)  None of these choices is correct. From this plot, it is reasonable to conclude that:


A) ( Δ\Delta H °\degree > 0, Δ\Delta S °\degree > 0)
B) ( Δ\Delta H °\degree > 0, Δ\Delta S °\degree < 0)
C) ( Δ\Delta H °\degree < 0, Δ\Delta S °\degree > 0)
D) ( Δ\Delta H °\degree < 0, Δ\Delta S °\degree < 0)
E) None of these choices is correct.

Correct Answer

verifed

verified

(p. Various sections) For a given reaction, a change in the pressure may result in a change in the sign of Δ\Delta G.

Correct Answer

verifed

verified

In the expression, S = k ln W, W is called the number of microstates. Explain clearly the meaning of the word "microstate," and why a system under a given set of conditions normally has many microstates.

Correct Answer

verifed

verified

A microstate is a specific, quantized st...

View Answer

Elemental boron can be formed by reaction of boron trichloride with hydrogen.  Elemental boron can be formed by reaction of boron trichloride with hydrogen.   Calculate  \Delta G \degree  for the reaction.   A)  -293.4 kJ B)  293.4 kJ C)  -102.8 kJ D)  102.8 kJ E)  None of these choices is correct. Calculate Δ\Delta G °\degree for the reaction.  Elemental boron can be formed by reaction of boron trichloride with hydrogen.   Calculate  \Delta G \degree  for the reaction.   A)  -293.4 kJ B)  293.4 kJ C)  -102.8 kJ D)  102.8 kJ E)  None of these choices is correct.


A) -293.4 kJ
B) 293.4 kJ
C) -102.8 kJ
D) 102.8 kJ
E) None of these choices is correct.

Correct Answer

verifed

verified

You are given pure samples of pentane, CH3CH2CH2CH2CH3(l) \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}(l) , and 1,3-pentadiene, CH2=CHCH=CHCH3(l) \mathrm{CH}_{2}=\mathrm{CHCH}=\mathrm{CHCH}_{3}(l) What prediction would you make concerning their standard molar entropies at 298 K?


A) S °\degree pentane > S °\degree 1,3-pentadiene
B) S °\degree pentane < S °\degree 1,3-pentadiene
C) S °\degree pentane \approx S °\degree 1,3-pentadiene
D) S °\degree pentane  S °\degree 1,3-pentadiene + 2* You are given pure samples of pentane,   \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}(l)   , and 1,3-pentadiene,   \mathrm{CH}_{2}=\mathrm{CHCH}=\mathrm{CHCH}_{3}(l)    What prediction would you make concerning their standard molar entropies at 298 K? A)  S \degree <sub>pentane</sub> > S \degree <sub>1,3-pentadiene</sub> B)  S  \degree <sub>pentane</sub> < S \degree <sub>1,3-pentadiene</sub> C)  S \degree <sub>pentane</sub>  \approx S \degree <sub>1,3-pentadiene</sub> D)  S \degree <sub>pentane</sub>  S \degree <sub>1,3-pentadiene</sub> + 2*  E)  More information is needed to make reasonable predictions.
E) More information is needed to make reasonable predictions.

Correct Answer

verifed

verified

State the second and third laws of thermodynamics.

Correct Answer

verifed

verified

All spontaneous processes are ...

View Answer

Which relationship or statement best describes Δ\Delta S °\degree for the following reaction? 2NH3(g) + 2ClF3(g) \rightarrow 6HF(g) + N2(g) + Cl2(g)


A) ( Δ\Delta SF °\degree\approx 0)
B) ( Δ\Delta S °\degree < 0)
C) ( Δ\Delta S °\degree > 0)
D) ( Δ\Delta S °\degree = Δ\Delta H °\degree /T)
E) More information is needed to make a reasonable prediction.

Correct Answer

verifed

verified

Which relationship or statement best describes Δ\Delta S °\degree for the following reaction?  Which relationship or statement best describes  \Delta S \degree  for the following reaction?   A)  ( \Delta S \degree   \approx  0)  B)  ( \Delta S \degree < 0)  C)  ( \Delta S \degree  > 0)  D)  ( \Delta S \degree  =  \Delta H \degree /T)  E)  More information is needed to make a reasonable prediction.


A) ( Δ\Delta S °\degree \approx 0)
B) ( Δ\Delta S °\degree < 0)
C) ( Δ\Delta S °\degree > 0)
D) ( Δ\Delta S °\degree = Δ\Delta H °\degree /T)
E) More information is needed to make a reasonable prediction.

Correct Answer

verifed

verified

Which of the following conditions will ensure that a chemical reaction will definitely proceed in the forward direction, toward products?


A) ( Δ\Delta H > 0)
B) ( Δ\Delta H < 0)
C) ( Δ\Delta Ssys > 0)
D) ( Δ\Delta Ssurr > Δ\Delta Ssys)
E) ( Δ\Delta S > Δ\Delta H/T)

Correct Answer

verifed

verified

Use the given data at 298 K to calculate Δ\Delta G °\degree for the reaction  Use the given data at 298 K to calculate  \Delta G \degree for the reaction     A)  129.3 kJ B)  133.6 kJ C)  196.0 kJ D)  199.8 kJ E)  229.6 kJ  Use the given data at 298 K to calculate  \Delta G \degree for the reaction     A)  129.3 kJ B)  133.6 kJ C)  196.0 kJ D)  199.8 kJ E)  229.6 kJ


A) 129.3 kJ
B) 133.6 kJ
C) 196.0 kJ
D) 199.8 kJ
E) 229.6 kJ

Correct Answer

verifed

verified

For a chemical reaction to be spontaneous at all temperatures, which of the following conditions must be met?


A) ( Δ\Delta S °\degree > 0, Δ\Delta H °\degree > 0)
B) ( Δ\Delta S °\degree > 0, Δ\Delta H °\degree < 0)
C) ( Δ\Delta S °\degree < 0, Δ\Delta H °\degree < 0)
D) ( Δ\Delta S °\degree < 0, Δ\Delta H °\degree > 0)
E) It is not possible for a reaction to be spontaneous at all temperatures.

Correct Answer

verifed

verified

Which relationship or statement best describes Δ\Delta S °\degree for the following reaction? HgS(s) + O2(g) \rightarrow Hg(l) + SO2(g)


A) ( Δ\Delta S °\degree\approx 0)
B) ( Δ\Delta S °\degree < 0)
C) ( Δ\Delta S °\degree > 0)
D) ( Δ\Delta S °\degree = Δ\Delta H °\degree /T)
E) More information is needed to make a reasonable prediction.

Correct Answer

verifed

verified

A certain process has Δ\Delta 0H °\degree > 0, Δ\Delta S °\degree < 0, and Δ\Delta G °\degree > 0. The values of Δ\Delta H °\degree and Δ\Delta S °\degree do not depend on the temperature. Which of the following is a correct conclusion about this process?


A) It is non-spontaneous at all T.
B) It is spontaneous at high T.
C) It is spontaneous at low T.
D) It is spontaneous at all T.
E) None of these conclusions is correct.

Correct Answer

verifed

verified

Which of the following is true for a system at equilibrium?


A) ( Δ\Delta S °\degree sys = Δ\Delta S °\degree surr)
B) ( Δ\Delta S °\degree sys = - Δ\Delta S °\degree surr)
C) ( Δ\Delta S °\degree sys = Δ\Delta S °\degree surr = 0
D) ( Δ\Delta S °\degree univ > 0)
E) None of these choices is a sufficient condition.

Correct Answer

verifed

verified

"A diamond is forever" is one of the most successful advertising slogans of all time. But is it true? For the reaction shown below, calculate the standard free energy change at 298 K and determine whether or not a diamond is "forever." C(diamond) °\degree C(graphite) Data: Δ\Delta Hf °\degree (diamond) = 1.895 kJ/mol; S °\degree (diamond) = 2.337 J mol¯11; S °\degree (graphite) = 5.740 J mol¯11.


A) ( Δ\Delta G °\degree = 2.19 kJ; forever
B) ( Δ\Delta G °\degree = -1.90 kJ; not forever)
C) ( Δ\Delta G °\degree = -2.90 kJ; not forever)
D) ( Δ\Delta G °\degree = 1.90 kJ; forever)
E) ( Δ\Delta G °\degree = < -1000 kJ; not forever)

Correct Answer

verifed

verified

Which one of the following phase changes decreases the entropy of the system?


A) melting
B) heating a gas
C) vaporization
D) condensation
E) sublimation

Correct Answer

verifed

verified

Showing 21 - 40 of 85

Related Exams

Show Answer