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Solve the problem -A herd of moose is introduced to a wildlife refuge. The number of moose, N(t) \mathrm { N } ( \mathrm { t } ) , after t\mathrm { t } years is described by the polynomial function N(t) =t3+24t+80N ( t ) = - t ^ { 3 } + 24 t + 80 . Use the Leading Coefficient Test to determine the graph's end behavior. What does this mean about what will eventually happen to the moose population?


A) The moose population in the refuge will grow out of control.
B) The moose population in the refuge will reach a constant amount greater than 0 .
C) The moose population in the refuge will be displaced by "oil" wells.
D) The moose population in the refuge will die out.

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Determine whether the graph of the polynomial has y-axis symmetry, origin symmetry, or neither. - f(x) =x3+x2+1f ( x ) = x ^ { 3 } + x ^ { 2 } + 1


A) yy -axis symmetry
B) origin symmetry
C) neither

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Find the coordinates of the vertex for the parabola defined by the given quadratic function. - f(x) =(x+4) 28f ( x ) = ( x + 4 ) ^ { 2 } - 8


A) (4,8) ( - 4 , - 8 )
B) (4,8) ( 4 , - 8 )
C) (4,8) ( 4,8 )
D) (4,8) ( - 4,8 )

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Determine whether the graph of the polynomial has y-axis symmetry, origin symmetry, or neither. - f(x) =x3(x+1) 2(x6) f ( x ) = - x ^ { 3 } ( x + 1 ) ^ { 2 } ( x - 6 )


A) y\mathrm { y } -axis symmetry
B) origin symmetry
C) neither

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Find the x-intercepts of the polynomial function. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each intercept. - f(x) =x2(x+4) (x2+1) f ( x ) = - x ^ { 2 } ( x + 4 ) \left( x ^ { 2 } + 1 \right)


A) 0 , touches the xx -axis and turns around;
4 , crosses the xx -axis
B) 0 , touches the xx -axis and turns around;
4- 4 , crosses the xx -axis;
1- 1 , crosses the x-axis;
1, crosses the x-axis;
C) 0 , touches the xx -axis and turns around;
4- 4 , crosses the xx -axis
D) 0 , touches the xx -axis and turns around;
4- 4 , crosses the xx -axis;
1- 1 , touches the xx -axis and turns around

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Use the vertex and intercepts to sketch the graph of the quadratic function. - f(x) =2x3+x2f ( x ) = - 2 x - 3 + x ^ { 2 }  Use the vertex and intercepts to sketch the graph of the quadratic function. - f ( x )  = - 2 x - 3 + x ^ { 2 }    A)    B)    C)    D)


A)
 Use the vertex and intercepts to sketch the graph of the quadratic function. - f ( x )  = - 2 x - 3 + x ^ { 2 }    A)    B)    C)    D)
B)
 Use the vertex and intercepts to sketch the graph of the quadratic function. - f ( x )  = - 2 x - 3 + x ^ { 2 }    A)    B)    C)    D)
C)
 Use the vertex and intercepts to sketch the graph of the quadratic function. - f ( x )  = - 2 x - 3 + x ^ { 2 }    A)    B)    C)    D)
D)
 Use the vertex and intercepts to sketch the graph of the quadratic function. - f ( x )  = - 2 x - 3 + x ^ { 2 }    A)    B)    C)    D)

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Determine whether the graph of the polynomial has y-axis symmetry, origin symmetry, or neither. - f(x) =4x2x3f ( x ) = 4 x ^ { 2 } - x ^ { 3 }


A) y-axis symmetry
B) origin symmetry
C) neither

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Find the x-intercepts (if any) for the graph of the quadratic function. - f(x) =x2+7x12f ( x ) = - x ^ { 2 } + 7 x - 12


A) (3,0) ( 3,0 ) and (4,0) ( - 4,0 )
B) No x-intercepts
C) (3,0) ( 3,0 ) and (4,0) ( 4,0 )
D) (3,0) ( - 3,0 ) and (4,0) ( - 4,0 )

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Find the x-intercepts of the polynomial function. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each intercept. - f(x) =6x2x3f ( x ) = 6 x ^ { 2 } - x ^ { 3 }


A) 0 , touches the xx -axis and turns around;
6 , crosses the xx -axis
B) 0 , crosses the xx -axis;
6\sqrt { 6 } , crosses the xx -axis;
6- \sqrt { 6 } , crosses the xx -axis
C) 0 , touches the xx -axis and turns around;
6 , touches the xx -axis and turns around
D) 0 , touches the xx -axis and turns around;
6\sqrt { 6 } , crosses the xx -axis;
6- \sqrt { 6 } , crosses the xx -axis

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Find the axis of symmetry of the parabola defined by the given quadratic function. - f(x) =7(x3) 26f ( x ) = - 7 ( x - 3 ) ^ { 2 } - 6


A) x=3x = - 3
B) x=3x = 3
C) x=6x = - 6
D) x=7x = - 7

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Solve the problem -The following table shows the number of speeding tickets issued in a county for the years 1994-1998, where 1 represents 1995, and so on.  Solve the problem -The following table shows the number of speeding tickets issued in a county for the years 1994-1998, where 1 represents 1995, and so on.    This data can be approximated using the third-degree polynomial  T ( x )  = - 0.67 x ^ { 3 } + 0.57 x ^ { 2 } + 63.80 x + 4213  Use the Leading Coefficient Test to determine the end behavior to the right for the graph of T. Will this function be useful in modeling the number of speeding tickets issued over an extended period of time? Explain your answer.  A)  The graph of T decreases without bound to the right. Since the number of larceny thefts will eventually decrease, the function T will be useful in modeling the number of speeding tickets issued over an extended period of time. B)  The graph of T decreases without bound to the right. This means that as  x  increases, the values of  T  will become more and more negative and the function will no longer model the number of speeding tickets issued. C)  The graph of  T  increases without bound to the right. This means that as  x  increases, the values of  T  will become large and positive and, since the values of T will become so large, the function will no longer model the number of speeding tickets issued. D)  The graph of  T  approaches zero for large values of  x . This means that  T  will not be useful in modeling the number of speeding tickets issued over an extended period. This data can be approximated using the third-degree polynomial T(x) =0.67x3+0.57x2+63.80x+4213T ( x ) = - 0.67 x ^ { 3 } + 0.57 x ^ { 2 } + 63.80 x + 4213 Use the Leading Coefficient Test to determine the end behavior to the right for the graph of T. Will this function be useful in modeling the number of speeding tickets issued over an extended period of time? Explain your answer.


A) The graph of T decreases without bound to the right. Since the number of larceny thefts will eventually decrease, the function T will be useful in modeling the number of speeding tickets issued over an extended period of time.
B) The graph of T decreases without bound to the right. This means that as xx increases, the values of TT will become more and more negative and the function will no longer model the number of speeding tickets issued.
C) The graph of TT increases without bound to the right. This means that as xx increases, the values of TT will become large and positive and, since the values of T will become so large, the function will no longer model the number of speeding tickets issued.
D) The graph of TT approaches zero for large values of xx . This means that TT will not be useful in modeling the number of speeding tickets issued over an extended period.

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Determine whether the given quadratic function has a minimum value or maximum value. Then find the coordinates of the minimum or maximum point. - f(x) =2x22x3f ( x ) = 2 x ^ { 2 } - 2 x - 3


A) maximum; (12,72) \left( \frac { 1 } { 2 } , - \frac { 7 } { 2 } \right)
B) minimum; (12,72) \left( \frac { 1 } { 2 } , - \frac { 7 } { 2 } \right)
C) maximum; (72,12) \left( - \frac { 7 } { 2 } , \frac { 1 } { 2 } \right)
D) minimum; (72,12) \left( - \frac { 7 } { 2 } , \frac { 1 } { 2 } \right)

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Determine the maximum possible number of turning points for the graph of the function. - f(x) =x7+3x8f ( x ) = x ^ { 7 } + 3 x ^ { 8 }


A) 1
B) 7
C) 3
D) 8

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Find the range of the quadratic function. - f(x) =2x2+2x8f ( x ) = 2 x ^ { 2 } + 2 x - 8


A) (,12]\left( - \infty , - \frac { 1 } { 2 } \right]
B) (,172]\left( - \infty , - \frac { 17 } { 2 } \right]
C) [172,) \left[ - \frac { 17 } { 2 } , \infty \right)
D) [12,) \left[ - \frac { 1 } { 2 } , \infty \right)

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Find the range of the quadratic function. - f(x) =5x2+15xf ( x ) = - 5 x ^ { 2 } + 15 x


A) (,32]\left( - \infty , \frac { 3 } { 2 } \right]
B) (,454]\left( - \infty , \frac { 45 } { 4 } \right]
C) (,32]\left( - \infty , - \frac { 3 } { 2 } \right]
D) (,454]\left( - \infty , - \frac { 45 } { 4 } \right]

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Use the Leading Coefficient Test to determine the end behavior of the polynomial function. Then use this end behavior to match the function with its graph. - f(x) =4x33x22x3f ( x ) = 4 x ^ { 3 } - 3 x ^ { 2 } - 2 x - 3


A) falls to the left and rises to the right
 Use the Leading Coefficient Test to determine the end behavior of the polynomial function. Then use this end behavior to match the function with its graph. - f ( x )  = 4 x ^ { 3 } - 3 x ^ { 2 } - 2 x - 3  A)  falls to the left and rises to the right   B)  rises to the left and falls to the right   C)  falls to the left and falls to the right   D)  rises to the left and rises to the right
B) rises to the left and falls to the right
 Use the Leading Coefficient Test to determine the end behavior of the polynomial function. Then use this end behavior to match the function with its graph. - f ( x )  = 4 x ^ { 3 } - 3 x ^ { 2 } - 2 x - 3  A)  falls to the left and rises to the right   B)  rises to the left and falls to the right   C)  falls to the left and falls to the right   D)  rises to the left and rises to the right
C) falls to the left and falls to the right
 Use the Leading Coefficient Test to determine the end behavior of the polynomial function. Then use this end behavior to match the function with its graph. - f ( x )  = 4 x ^ { 3 } - 3 x ^ { 2 } - 2 x - 3  A)  falls to the left and rises to the right   B)  rises to the left and falls to the right   C)  falls to the left and falls to the right   D)  rises to the left and rises to the right
D) rises to the left and rises to the right
 Use the Leading Coefficient Test to determine the end behavior of the polynomial function. Then use this end behavior to match the function with its graph. - f ( x )  = 4 x ^ { 3 } - 3 x ^ { 2 } - 2 x - 3  A)  falls to the left and rises to the right   B)  rises to the left and falls to the right   C)  falls to the left and falls to the right   D)  rises to the left and rises to the right

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Find the x-intercepts of the polynomial function. State whether the graph crosses the x-axis, or touches the x-axis and turns around, at each intercept. - x4+3x310x2=0x ^ { 4 } + 3 x ^ { 3 } - 10 x ^ { 2 } = 0


A) 0 , touches the xx -axis and turns around;
5 , crosses the xx -axis;
2- 2 , crosses the xx -axis
B) 0 , touches the xx -axis and turns around;
5 , touches the xx -axis and turns around;
2- 2 , touches the xx -axis and turns around
C) 0 , crosses the xx -axis;
5- 5 , crosses the xx -axis;
2 , crosses the xx -axis
D) 0 , touches the xx -axis and turns around;
5- 5 , crosses the xx -axis;
2 , crosses the xx -axis

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Determine whether the graph shown is the graph of a polynomial function. -Determine whether the graph shown is the graph of a polynomial function. -  A) not a polynomial function B) polynomial function


A) not a polynomial function
B) polynomial function

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Determine whether the given quadratic function has a minimum value or maximum value. Then find the coordinates of the minimum or maximum point. - f(x) =2x2+6xf ( x ) = - 2 x ^ { 2 } + 6 x


A) minimum; (32,92) \left( - \frac { 3 } { 2 } , - \frac { 9 } { 2 } \right)
B) minimum; (32,92) \left( \frac { 3 } { 2 } , \frac { 9 } { 2 } \right)
C) maximum; (32,92) \left( - \frac { 3 } { 2 } , - \frac { 9 } { 2 } \right)
D) maximum; (32,92) \left( \frac { 3 } { 2 } , \frac { 9 } { 2 } \right)

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Find the axis of symmetry of the parabola defined by the given quadratic function. - f(x) =11(x3) 2+5f ( x ) = 11 ( x - 3 ) ^ { 2 } + 5


A) x=3x = - 3
B) x=3x = 3
C) x=11x = 11
D) x=5x = 5

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