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In the following fission reaction,identify the other product: In the following fission reaction,identify the other product: U + n \to I + 2 n + __________ A) Y B) Y C) Mo D) Mo E) Zr U + In the following fission reaction,identify the other product: U + n \to I + 2 n + __________ A) Y B) Y C) Mo D) Mo E) Zr n →\to In the following fission reaction,identify the other product: U + n \to I + 2 n + __________ A) Y B) Y C) Mo D) Mo E) Zr I + 2 In the following fission reaction,identify the other product: U + n \to I + 2 n + __________ A) Y B) Y C) Mo D) Mo E) Zr n + __________


A) In the following fission reaction,identify the other product: U + n \to I + 2 n + __________ A) Y B) Y C) Mo D) Mo E) Zr Y
B) In the following fission reaction,identify the other product: U + n \to I + 2 n + __________ A) Y B) Y C) Mo D) Mo E) Zr Y
C) In the following fission reaction,identify the other product: U + n \to I + 2 n + __________ A) Y B) Y C) Mo D) Mo E) Zr Mo
D) In the following fission reaction,identify the other product: U + n \to I + 2 n + __________ A) Y B) Y C) Mo D) Mo E) Zr Mo
E) In the following fission reaction,identify the other product: U + n \to I + 2 n + __________ A) Y B) Y C) Mo D) Mo E) Zr Zr

F) A) and B)
G) All of the above

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Identify the missing particle in the following equation: Identify the missing particle in the following equation: U \to He + ? A) Pu B) Th C) Th D) U E) none of these U →\to Identify the missing particle in the following equation: U \to He + ? A) Pu B) Th C) Th D) U E) none of these He + ?


A) Identify the missing particle in the following equation: U \to He + ? A) Pu B) Th C) Th D) U E) none of these Pu
B) Identify the missing particle in the following equation: U \to He + ? A) Pu B) Th C) Th D) U E) none of these Th
C) Identify the missing particle in the following equation: U \to He + ? A) Pu B) Th C) Th D) U E) none of these Th
D) Identify the missing particle in the following equation: U \to He + ? A) Pu B) Th C) Th D) U E) none of these U
E) none of these

F) A) and B)
G) None of the above

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The number of a certain radioactive nuclide present in a sample decays from 160.to 20.in 39 minutes.What is the half-life of this radioactive species?


A) 8 minutes
B) 13 minutes
C) 18 minutes
D) 23 minutes
E) 28 minutes

F) B) and E)
G) A) and D)

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Calculate the change in energy in kJ/mol for the transmutation of radium from the given molar masses: Calculate the change in energy in kJ/mol for the transmutation of radium from the given molar masses: A) -5.2 kJ/mol B) -1.6 kJ/mol C) -4.7 \times 10<sup>14</sup> kJ/mol D) -4.7 \times 10<sup>8</sup> kJ/mol E) +1.6 \times 10<sup>8</sup> kJ/mol


A) -5.2 kJ/mol
B) -1.6 kJ/mol
C) -4.7 ×\times 1014 kJ/mol
D) -4.7 ×\times 108 kJ/mol
E) +1.6 ×\times 108 kJ/mol

F) A) and B)
G) C) and D)

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The I-131 nuclide has a half-life of 8.0 days.If you originally have a 1.8-kg sample,after 1.4 months you will have approximately


A) 95 g
B) 62 g
C) 71 g
D) 47 g
E) less than 1 g

F) A) and D)
G) A) and C)

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The half-life of The half-life of is 28 years.How long will it take for a given sample of to be 89% decomposed? A) 9.0 half-lives B) 5 years C) 89 years D) 2.2 years E) none of these is 28 years.How long will it take for a given sample of The half-life of is 28 years.How long will it take for a given sample of to be 89% decomposed? A) 9.0 half-lives B) 5 years C) 89 years D) 2.2 years E) none of these to be 89% decomposed?


A) 9.0 half-lives
B) 5 years
C) 89 years
D) 2.2 years
E) none of these

F) B) and E)
G) A) and E)

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The nuclide The nuclide Th is radioactive.When one of these atoms decays,a series of \alpha and \beta -particle emissions occurs,taking the atom through many transformations to end up as an atom of Pb.How many \alpha particles are emitted in converting Th into Pb? A) 6 B) 8 C) 2 D) 214 E) 4 Th is radioactive.When one of these atoms decays,a series of α\alpha and β\beta -particle emissions occurs,taking the atom through many transformations to end up as an atom of The nuclide Th is radioactive.When one of these atoms decays,a series of \alpha and \beta -particle emissions occurs,taking the atom through many transformations to end up as an atom of Pb.How many \alpha particles are emitted in converting Th into Pb? A) 6 B) 8 C) 2 D) 214 E) 4 Pb.How many α\alpha particles are emitted in converting The nuclide Th is radioactive.When one of these atoms decays,a series of \alpha and \beta -particle emissions occurs,taking the atom through many transformations to end up as an atom of Pb.How many \alpha particles are emitted in converting Th into Pb? A) 6 B) 8 C) 2 D) 214 E) 4 Th into The nuclide Th is radioactive.When one of these atoms decays,a series of \alpha and \beta -particle emissions occurs,taking the atom through many transformations to end up as an atom of Pb.How many \alpha particles are emitted in converting Th into Pb? A) 6 B) 8 C) 2 D) 214 E) 4 Pb?


A) 6
B) 8
C) 2
D) 214
E) 4

F) C) and D)
G) A) and D)

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The smallest amount of radioactive material that will support a self-sustained fission reaction is called the


A) molar mass
B) moderator
C) supercritical mass
D) subcritical mass
E) critical mass

F) A) and E)
G) B) and C)

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The most likely decay mode (or modes) of the unstable nuclide The most likely decay mode (or modes) of the unstable nuclide C would be: A) positron production B) ( \alpha -particle production) C) electron capture D) ( \beta -particle production) E) either positron production or electron capture,or both. C would be:


A) positron production
B) ( α\alpha -particle production)
C) electron capture
D) ( β\beta -particle production)
E) either positron production or electron capture,or both.

F) B) and D)
G) A) and E)

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Use the following data to determine the expected 14C activity in the Shroud of Turin.The atmospheric activity of 14C is 15 cpm/gC (counts per minute per gram of carbon) .Assume that the cloth was made in the year 24 A.D.The half-life of 14C is 5730 years.


A) 28 cpm/gC
B) 7.3 cpm/gC
C) 5.1 cpm/gC
D) 11 cpm/gC
E) 12 cpm/gC

F) B) and E)
G) All of the above

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The Fe-56 nucleus is known to be stable.Answer the following questions. -What is the most likely decay for the Fe-53 nucleus?


A) ( β\beta decay)
B) positron emission
C) ( α\alpha decay)
D) ( γ\gamma -ray emission)
E) two of these

F) C) and E)
G) A) and C)

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Electron capture transforms Electron capture transforms K into what nuclide? A) Ca B) Ar C) He D) K<sup>-</sup> E) Ca K into what nuclide?


A) Electron capture transforms K into what nuclide? A) Ca B) Ar C) He D) K<sup>-</sup> E) Ca Ca
B) Electron capture transforms K into what nuclide? A) Ca B) Ar C) He D) K<sup>-</sup> E) Ca Ar
C) Electron capture transforms K into what nuclide? A) Ca B) Ar C) He D) K<sup>-</sup> E) Ca He
D) Electron capture transforms K into what nuclide? A) Ca B) Ar C) He D) K<sup>-</sup> E) Ca K-
E) Electron capture transforms K into what nuclide? A) Ca B) Ar C) He D) K<sup>-</sup> E) Ca Ca

F) A) and E)
G) B) and E)

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The bismuth-209 nucleus has a binding energy per nucleon of 7.6514 MeV.(1 MeV is 1.60 ×\times 10-13 J) .Determine the difference in mass between one mole of bismuth-209 nuclei and the component nucleons of which it is made.


A) 1.71 ×\times 10-3 kg
B) 3.92 ×\times 10-8 kg
C) 8.20 ×\times 10-6 kg
D) 2.56 ×\times 10-10 kg
E) 6.81 ×\times 10-4 kg

F) B) and C)
G) All of the above

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A radioactive element has a half-life of 1.6 hours.How many hours will it take for the number of atoms present to decay to one-sixteenth of the initial value?


A) 26
B) 13
C) 6.4
D) 0.15
E) 16

F) All of the above
G) A) and B)

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What component of a nuclear reactor moderates the rate of the reaction?


A) steam turbine
B) control rods
C) cooling water
D) containment shell
E) cyclotron

F) A) and D)
G) B) and E)

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A certain radioactive sample contains 2.4 ×\times 103 nuclides at a certain time (t = 0) ;3.0 h later the sample contains 6.0 ×\times 102 nuclides. -The value of the rate constant for this process is:


A) 2.2 h-1
B) 4.6 ×\times 10-1 h-1
C) 1.6 h-1
D) 3.0 h-1
E) none of these

F) C) and D)
G) A) and B)

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Consider a certain type of nucleus that has a half-life of 32 min.Calculate the percent of original sample of nuclides remaining after 2.5 hours have passed.


A) 96%
B) 40%
C) 6.9%
D) 3.9%
E) 3.2%

F) A) and C)
G) A) and D)

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Breeder reactors are used to convert the nonfissionable nuclide Breeder reactors are used to convert the nonfissionable nuclide U to a fissionable product.Neutron capture of the U is followed by two successive beta decays.What is the final fissionable product? A) Pu B) Ra C) U D) Pu E) Np U to a fissionable product.Neutron capture of the Breeder reactors are used to convert the nonfissionable nuclide U to a fissionable product.Neutron capture of the U is followed by two successive beta decays.What is the final fissionable product? A) Pu B) Ra C) U D) Pu E) Np U is followed by two successive beta decays.What is the final fissionable product?


A) Breeder reactors are used to convert the nonfissionable nuclide U to a fissionable product.Neutron capture of the U is followed by two successive beta decays.What is the final fissionable product? A) Pu B) Ra C) U D) Pu E) Np Pu
B) Breeder reactors are used to convert the nonfissionable nuclide U to a fissionable product.Neutron capture of the U is followed by two successive beta decays.What is the final fissionable product? A) Pu B) Ra C) U D) Pu E) Np Ra
C) Breeder reactors are used to convert the nonfissionable nuclide U to a fissionable product.Neutron capture of the U is followed by two successive beta decays.What is the final fissionable product? A) Pu B) Ra C) U D) Pu E) Np U
D) Breeder reactors are used to convert the nonfissionable nuclide U to a fissionable product.Neutron capture of the U is followed by two successive beta decays.What is the final fissionable product? A) Pu B) Ra C) U D) Pu E) Np Pu
E) Breeder reactors are used to convert the nonfissionable nuclide U to a fissionable product.Neutron capture of the U is followed by two successive beta decays.What is the final fissionable product? A) Pu B) Ra C) U D) Pu E) Np Np

F) D) and E)
G) A) and D)

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The lead-208 nucleus has a mass defect of 1.714 g/mol. Determine the binding energy per nucleon for lead-208 nuclei.(1 MeV is 1.602 ×\times 10-13 J) .


A) 1.597 ×\times 10-4 MeV
B) 1.597 ×\times 103 MeV
C) 19.47 MeV
D) 24.68 MeV
E) 7.677 MeV

F) B) and E)
G) B) and C)

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One of the hopes for solving the world's energy problem is to make use of the fusion reaction: One of the hopes for solving the world's energy problem is to make use of the fusion reaction: H + H \to He + n + energy How much energy is released when one mole of deuterium is fused with one mole of tritium according to the above reaction? The masses of the atoms and the neutrons are: H = 2.0140 amu H = 3.01605 amu He = 4.002603 amu n = 1.008665 amu The speed of light is 2.9979 \times 10<sup>8</sup> m/s A) 5.63 \times 10<sup>8</sup> J B) 56.3 J C) 1.69 \times 10<sup>12</sup> J D) 7.84 \times 10<sup>44</sup> J E) 8.44 \times 10<sup>11</sup> J H + One of the hopes for solving the world's energy problem is to make use of the fusion reaction: H + H \to He + n + energy How much energy is released when one mole of deuterium is fused with one mole of tritium according to the above reaction? The masses of the atoms and the neutrons are: H = 2.0140 amu H = 3.01605 amu He = 4.002603 amu n = 1.008665 amu The speed of light is 2.9979 \times 10<sup>8</sup> m/s A) 5.63 \times 10<sup>8</sup> J B) 56.3 J C) 1.69 \times 10<sup>12</sup> J D) 7.84 \times 10<sup>44</sup> J E) 8.44 \times 10<sup>11</sup> J H →\to One of the hopes for solving the world's energy problem is to make use of the fusion reaction: H + H \to He + n + energy How much energy is released when one mole of deuterium is fused with one mole of tritium according to the above reaction? The masses of the atoms and the neutrons are: H = 2.0140 amu H = 3.01605 amu He = 4.002603 amu n = 1.008665 amu The speed of light is 2.9979 \times 10<sup>8</sup> m/s A) 5.63 \times 10<sup>8</sup> J B) 56.3 J C) 1.69 \times 10<sup>12</sup> J D) 7.84 \times 10<sup>44</sup> J E) 8.44 \times 10<sup>11</sup> J He + One of the hopes for solving the world's energy problem is to make use of the fusion reaction: H + H \to He + n + energy How much energy is released when one mole of deuterium is fused with one mole of tritium according to the above reaction? The masses of the atoms and the neutrons are: H = 2.0140 amu H = 3.01605 amu He = 4.002603 amu n = 1.008665 amu The speed of light is 2.9979 \times 10<sup>8</sup> m/s A) 5.63 \times 10<sup>8</sup> J B) 56.3 J C) 1.69 \times 10<sup>12</sup> J D) 7.84 \times 10<sup>44</sup> J E) 8.44 \times 10<sup>11</sup> J n + energy How much energy is released when one mole of deuterium is fused with one mole of tritium according to the above reaction? The masses of the atoms and the neutrons are: One of the hopes for solving the world's energy problem is to make use of the fusion reaction: H + H \to He + n + energy How much energy is released when one mole of deuterium is fused with one mole of tritium according to the above reaction? The masses of the atoms and the neutrons are: H = 2.0140 amu H = 3.01605 amu He = 4.002603 amu n = 1.008665 amu The speed of light is 2.9979 \times 10<sup>8</sup> m/s A) 5.63 \times 10<sup>8</sup> J B) 56.3 J C) 1.69 \times 10<sup>12</sup> J D) 7.84 \times 10<sup>44</sup> J E) 8.44 \times 10<sup>11</sup> J H = 2.0140 amu One of the hopes for solving the world's energy problem is to make use of the fusion reaction: H + H \to He + n + energy How much energy is released when one mole of deuterium is fused with one mole of tritium according to the above reaction? The masses of the atoms and the neutrons are: H = 2.0140 amu H = 3.01605 amu He = 4.002603 amu n = 1.008665 amu The speed of light is 2.9979 \times 10<sup>8</sup> m/s A) 5.63 \times 10<sup>8</sup> J B) 56.3 J C) 1.69 \times 10<sup>12</sup> J D) 7.84 \times 10<sup>44</sup> J E) 8.44 \times 10<sup>11</sup> J H = 3.01605 amu One of the hopes for solving the world's energy problem is to make use of the fusion reaction: H + H \to He + n + energy How much energy is released when one mole of deuterium is fused with one mole of tritium according to the above reaction? The masses of the atoms and the neutrons are: H = 2.0140 amu H = 3.01605 amu He = 4.002603 amu n = 1.008665 amu The speed of light is 2.9979 \times 10<sup>8</sup> m/s A) 5.63 \times 10<sup>8</sup> J B) 56.3 J C) 1.69 \times 10<sup>12</sup> J D) 7.84 \times 10<sup>44</sup> J E) 8.44 \times 10<sup>11</sup> J He = 4.002603 amu One of the hopes for solving the world's energy problem is to make use of the fusion reaction: H + H \to He + n + energy How much energy is released when one mole of deuterium is fused with one mole of tritium according to the above reaction? The masses of the atoms and the neutrons are: H = 2.0140 amu H = 3.01605 amu He = 4.002603 amu n = 1.008665 amu The speed of light is 2.9979 \times 10<sup>8</sup> m/s A) 5.63 \times 10<sup>8</sup> J B) 56.3 J C) 1.69 \times 10<sup>12</sup> J D) 7.84 \times 10<sup>44</sup> J E) 8.44 \times 10<sup>11</sup> J n = 1.008665 amu The speed of light is 2.9979 ×\times 108 m/s


A) 5.63 ×\times 108 J
B) 56.3 J
C) 1.69 ×\times 1012 J
D) 7.84 ×\times 1044 J
E) 8.44 ×\times 1011 J

F) D) and E)
G) A) and B)

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